Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 29 - Molecules and Solids - Problems - Page 855: 28

Answer

a. 1.9 mA. b. 3.9 mA.

Work Step by Step

a. We are asked to make a very rough approximation. See Figure 29-31. We see that half the time, the current is zero. A rough approximation says that the average current is half of the full rms current. $$I_{average}=\frac{1}{2}\frac{V_{rms}}{R}=\frac{1}{2}\frac{120V}{31k\Omega}=1.9mA$$ b. We are asked to make a very rough approximation. See Figure 29-32. The sine wave is modified so that the current is positive all of the time. A rough approximation says that the average current is equal to the full rms current. $$I_{average}=\frac{V_{rms}}{R}=\frac{120V}{31k\Omega}=3.9mA$$
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