Answer
110 pm, 150 pm, 133 pm.
Work Step by Step
Follow the procedure suggested in the problem.
HN: $\frac{1}{2}(d_{H_2}+d_{N_2})=\frac{1}{2}(74pm+145pm)=110pm$
CN: $\frac{1}{2}(d_{C_2}+d_{N_2})=\frac{1}{2}(154pm+145pm)=110pm$
NO: $\frac{1}{2}(d_{N_2}+d_{O_2})=\frac{1}{2}(145pm+121pm)=133pm$