Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 29 - Molecules and Solids - Problems - Page 854: 23

Answer

The factor is about 3.3 million.

Work Step by Step

Calculate the number of conduction electrons in 1 mole of pure silicon. $$N_{Si}=\left(\frac{28.09\times10^{-3}kg/mol}{2330kg/m^3}\right)(10^{16}electons/m^3)=1.2\times10^{11}$$ Now find the extra conduction electrons provided if the silicon is doped. $$N_{doping}=\left(\frac{6.02\times10^{23}atoms}{1.5\times10^6}\right) =4.0\times10^{17}$$ Take the ratio of the two numbers of conduction electrons to find the factor by which the density of conduction electrons is increased. $$\frac{ N_{doping}}{N_{Si}}=\frac{4.013\times10^{17}}{1.206\times10^{11}}\approx 3.3\times10^6$$
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