Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 56

Answer

49.4 nm

Work Step by Step

The longest wavelength photon has an energy equal to the sum of the ionization energy (13.6 eV) and the kinetic energy (11.5 eV). $$ E_{total} =hf = \frac{hc}{\lambda}$$ In this problem, the value of hc is useful. Use the result stated in Problem 29, $hc=1240\;eV \cdot nm$. $$ \lambda=\frac{hc}{E_{total}}=\frac{1240\;eV \cdot nm }{13.6eV+11.5eV}=49.4 nm$$
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