Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 46

Answer

$v=3.9\times10^{-38}m/s$; This is significantly lower than normal freeway speeds.

Work Step by Step

For diffraction effects to be important, the wavelength is roughly the size of the opening. Use equation 27–8. $$\lambda=\frac{h}{p}=\frac{h}{mv}$$ $$v =\frac{h}{m \lambda}$$ $$v=\frac{6.63\times10^{-34}J \cdot s }{(1400kg)(12m)}=3.9\times10^{-38}m/s$$ This is about a factor of $10^{39}$ below ordinary highway speeds of 30 m/s.
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