Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 33

Answer

2.62 MeV

Work Step by Step

By conservation of mass-energy, the photon energy equals the mass energy of the products plus the kinetic energy of the products. The positron and electron have equal mass. $$E_{photon}=KE_{products}+m_{e}c^2+m_{pos}c^2$$ $$ KE_{products}=E_{photon}-2\times m_{e}c^2$$ $$ KE_{products}=3.64MeV-2(0.511MeV)=2.62 MeV$$
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