Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - General Problems - Page 801: 67

Answer

$3.28\times10^{15}Hz$

Work Step by Step

The minimum energy of the photon is 13.6 eV because it must ionize the hydrogen atom. Find the minimum frequency using equation 27–4. $$E=hf$$ $$f=\frac{E}{h}=\frac{(13.6eV)(1.60\times10^{-19}J/eV)}{6.63\times10^{-34}J \cdot s}$$ $$f=3.28\times10^{15}Hz$$
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