Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 27

Answer

1.6 GeV/c.

Work Step by Step

The kinetic energy is given by equation 26–5b. Find $\gamma$. $$KE=950MeV=(\gamma-1)mc^2=(\gamma-1)(938.3MeV)$$ $$\gamma = 2.012$$ Use equation 26-2 to solve for the corresponding v of 0.8678c. The momentum is given by equation 26–4. $$p=\gamma mv=2.012(938.3MeV/c^2)(0.8678c)=1638MeV/c\approx 1.6GeV/c$$
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