Answer
2.7 GeV, 3.5 GeV/c.
Work Step by Step
Find $\gamma$ for this proton. Note that v/c = 0.9667.
$$\gamma=\frac{1}{\sqrt{1-v^2/c^2}}=\frac{1}{\sqrt{1-0.9667^2}}=3.9075$$
The kinetic energy is given by equation 26–5b.
$$KE=(\gamma-1)mc^2=(3.9075-1)(938.3MeV)$$
$$=2728.2MeV\approx2.7GeV$$
The momentum is given by equation 26–4.
$$p=\gamma mv=3.9075(938.3MeV/c^2)(0.9667c)$$
$$=3554MeV/c\approx 3.5GeV/c$$