Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 24

Answer

$ m=939\frac{MeV}{c^2}$

Work Step by Step

The mass is found by using equation 26–7. $$E=mc^2$$ $$m=\frac{E}{c^2}=\frac{1}{c^2}mc^2$$ $$m=\frac{1}{c^2}\frac{(1.67\times10^{-27}kg) (3.00\times10^8m/s)^2}{1.60\times10^{-13}J/MeV}$$ $$m=939\frac{MeV}{c^2}$$ (If we had used more significant figures for the calculation, the answer would have been $938\frac{MeV}{c^2}$.)
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