Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 21

Answer

0.512 MeV

Work Step by Step

The rest energy of the electron is found by using equation 26–7. $$E=mc^2=(9.11\times10^{-31}kg)(3.00\times10^8m/s)^2=8.20\times10^{-14}J$$ Convert to MeV using the given conversion factor to find a rest mass of 0.512 MeV. (If we had used more significant figures for the calculation, the answer would have been 0.511 MeV.)
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