Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 17

Answer

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Work Step by Step

a. Divide the classical expression for momentum by the relativistic momentum. $$\frac{mv}{mv/(\sqrt{1-v^2/c^2})}=\sqrt{1-v^2/c^2}=\sqrt{1-0.15^2}=0.989$$ We see that the expression, mv, is too low by about $1.1\%$. b. Repeat for v = 0.75c. $$\frac{mv}{mv/(\sqrt{1-v^2/c^2})}=\sqrt{1-v^2/c^2}=\sqrt{1-0.75^2}=0.661$$ We see that the expression, mv, is too low by about $34\%$.
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