Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - Problems - Page 768: 16

Answer

$4.6\times10^{-19}kg \cdot m/s$

Work Step by Step

Find the momentum using equation 26–4. $$p=\gamma mv=\frac{mv}{\sqrt{1-v^2/c^2}}$$ $$p=\frac{(1.67\times10^{-27}kg)(0.68)(3.00\times10^8m/s)}{\sqrt{1-0.68^2}}$$ $$p=4.6\times10^{-19}kg \cdot m/s$$
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