Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 26 - The Special Theory of Relativity - General Problems - Page 769: 64

Answer

28.32 MeV.

Work Step by Step

The required energy provides the increase in rest energy. $$E=[(2m_{p+e}+2m_n)-m_{He}]c^2$$ $$E=[(2(1.00783u)+2(1.00867u))-4.00260u]c^2(\frac{931.5MeV/c^2}{u})$$ $$=28.32MeV$$ This is the total binding energy of the helium nucleus.
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