Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 742: 58

Answer

See answers.

Work Step by Step

Use equation 25-8. The resolving power (RP) is the focal length of the lens, multiplied by the angular resolution. The resolution limit is the reciprocal of the resolving power. Calculate the resolution limit for the maximum aperture diameter. $$\frac{1}{RP(f/2)}=(\frac{1.22\lambda f}{D})^{-1}=\frac{D}{1.22\lambda f}$$ $$=\frac{25mm}{1.22(560\times10^{-6}mm)(50.0mm)}=730\;lines/mm$$ Calculate it for the minimum aperture diameter. $$\frac{1}{RP(f/16)}=(\frac{1.22\lambda f}{D})^{-1}=\frac{D}{1.22\lambda f}$$ $$=\frac{3.0mm}{1.22(560\times10^{-6}mm)(50.0mm)}=88\;lines/mm$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.