Answer
See answers.
Work Step by Step
Use equation 25-8. The resolving power (RP) is the focal length of the lens, multiplied by the angular resolution.
The resolution limit is the reciprocal of the resolving power.
Calculate the resolution limit for the maximum aperture diameter.
$$\frac{1}{RP(f/2)}=(\frac{1.22\lambda f}{D})^{-1}=\frac{D}{1.22\lambda f}$$
$$=\frac{25mm}{1.22(560\times10^{-6}mm)(50.0mm)}=730\;lines/mm$$
Calculate it for the minimum aperture diameter.
$$\frac{1}{RP(f/16)}=(\frac{1.22\lambda f}{D})^{-1}=\frac{D}{1.22\lambda f}$$
$$=\frac{3.0mm}{1.22(560\times10^{-6}mm)(50.0mm)}=88\;lines/mm$$