Answer
The lens was moved 3.9 cm toward the fine print.
Work Step by Step
The focal length f is +12 cm.
Use the lens equation to find the object distance. First, the image distance is infinity.
$$\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{d_o}+\frac{1}{\infty}$$
$$d_o=f=12cm$$
Second, the image distance is -25 cm. The virtual image is at his near point, and the eye is very close to the lens. Find the object distance now.
$$\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}$$
$$d_o=\frac{fd_i}{d_i-f}=\frac{(12cm) (-25cm) }{-25cm-12cm}=8.1cm$$
The lens was moved closer to the fine print, by a distance of $12cm-8.1cm=3.9cm$.