Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 740: 28

Answer

Image distance is -61 cm, magnification is 2.7.

Work Step by Step

Use the lens equation to find the image distance. $$\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}$$ $$d_i=\frac{fd_o}{d_o-f}=\frac{(9.2cm)(8.0cm)}{8.0cm-9.2cm}=-61cm$$ b. Assume that the eye is relaxed, since the image is relatively far away compared to the near point. The angular magnification is found from equation 25-2a. $$M=\frac{\theta ‘}{\theta}=\frac{N}{f}=\frac{25cm}{9.2cm}=2.7\times$$ Note: it is not appropriate to use $M=N/d_o$, as on page 723, because the image is not at the eye’s near point.
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