Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 25 - Optical Instruments - Problems - Page 740: 22

Answer

7.8 cm

Work Step by Step

Find the focal length from equation 25–2a for the relaxed normal eye. $$M=\frac{N}{f}$$ $$f=\frac{N}{M}=\frac{25cm}{3.2}=7.8cm$$
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