Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 51

Answer

a) $d_o=7cm$ b) $d_o=3cm$

Work Step by Step

$f=5cm$ $m=2.5$ a) $d_o=\frac{1}{\frac{1}{5cm}-\frac{1}{d_i}}$ $\frac{d_i}{d_o}=2.5$ $d_o=\frac{1}{\frac{1}{5cm}-\frac{1}{2.5d_o}}$ $d_o=\frac{12.5d_o}{2.5d_o-5cm}$ $2.5d_o-5cm-12.5cm=0$ $d_o=7cm$ b) $d_o=\frac{1}{\frac{1}{5cm}-\frac{1}{d_i}}$ $\frac{d_i}{d_o}=-2.5$ $d_o=\frac{1}{\frac{1}{5cm}-\frac{1}{-2.5d_o}}$ $d_o=\frac{12.5d_o}{2.5d_o+5cm}$ $2.5d_o+5cm=12.5cm$ $d_o=3cm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.