Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 49

Answer

$d_i=-6.67cm$ Same side as the object Virtual and Upright $m=-0.534$ $h_i=0.534mm$

Work Step by Step

$f=\frac{1}{-7.00D}=-14.3cm$ $d_o=12.5cm$ $h_o=0.1cm$ $d_i=\frac{1}{\frac{1}{f}-\frac{1}{d_o}}=\frac{1}{\frac{1}{-14.3cm}-\frac{1}{12.5cm}}=-6.67cm$ The image is on the same side as the object. Therefore, it is a virtual and upright image. $m=\frac{d_i}{d_o}=\frac{-6.67cm}{12.5cm}=-0.534$ The image is $h_i=0.534mm$, almost two times smaller than the ant.
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