Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 36

Answer

1.36

Work Step by Step

Use equation 23–6. $$sin\theta_C=\frac{n_{air}}{n_{liquid}}$$ $$ n_{liquid} =\frac{n_{air}}{ sin\theta_C }=\frac{1}{sin47.2^{\circ}}=1.36$$
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