Answer
$d=4.38m$
Work Step by Step
$\theta=\arctan(\frac{1.3m}{2.5m})=27.5^o$
$\theta=\arcsin(\frac{1\sin(90^o-27.5^o)}{1.33})=41.8^o$
$d=2.5m+(2.1m\tan(41.8^o))=4.38m$
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