Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 675: 34

Answer

$d=4.38m$

Work Step by Step

$\theta=\arctan(\frac{1.3m}{2.5m})=27.5^o$ $\theta=\arcsin(\frac{1\sin(90^o-27.5^o)}{1.33})=41.8^o$ $d=2.5m+(2.1m\tan(41.8^o))=4.38m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.