Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 674: 24

Answer

$d_i=1.707r$ $m=-2.41$

Work Step by Step

$r=d_o+d_i$ $d_o=r-d_i$ $d_i=\frac{1}{\frac{1}{f}-\frac{1}{d_o}}=\frac{1}{\frac{2}{r}-\frac{1}{d_o}}=\frac{1}{\frac{2}{r}-\frac{1}{r-d_i}}=\frac{r^2-rd_i}{3r-2d_i}$ $r^2-4rd_i+2di^2=0$ $d_i=1.707r$ $d_i=0.293r$ The first solution is the answer $m=-\frac{d_i}{d_o}=-\frac{d_i}{r-d_i}=-2.41$
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