Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - Problems - Page 674: 22

Answer

See image and solution

Work Step by Step

$f=\frac{r}{2}$ $\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$ $d_i=\frac{1}{\frac{1}{f}-\frac{1}{d_o}}=\frac{1}{\frac{2}{r}-\frac{1}{d_o}}=\frac{rd_o}{2d_o-r}$ $m=\frac{h_i}{h_o}=-\frac{d_i}{d_o}=\frac{r}{r-2d_o}$ If $d_o>r$, $|m|<1$ If $f1$
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