Answer
The image is 2.0 cm behind the surface of the ball, virtual, and upright.
Work Step by Step
Use the mirror equation, 23–2.
$$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$
Solve for the image distance.
The object distance is 25.0 cm.
The focal length is half the radius, and is negative because the ball acts as a convex mirror. The radius is 4.4 cm, so $f=-2.2 cm$.
$$d_i=\frac{d_of}{d_o-f}=\frac{(25.0cm)(-2.2cm)}{25.0cm-(-2.2cm)}$$
$$=-2.02cm$$
The image is 2.0 cm behind the surface of the ball, and virtual.
Calculate the magnification.
$$m=-\frac{d_i}{d_o}=-\frac{-2.022cm}{25.0cm}=+0.081$$
The magnification is positive. The image is upright.