Answer
a) See image. approximately 5 cm
b) $d_i=-5.3cm$
c) $h_i=0.099cm$
Work Step by Step
a) See image. approximately 5 cm
b) $\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$
$d_i=\frac{1}{\frac{1}{f}-\frac{1}{d_o}}=\frac{1}{\frac{1}{-8.0cm}-\frac{1}{16cm}}=-5.3cm$
c) $h_i=\frac{h_od_i}{d_o}=\frac{(0.3cm)(5.3cm)}{16cm}=0.099cm$