Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - General Problems - Page 676: 71

Answer

6.04 m.

Work Step by Step

Use Snell’s Law to find the angle of incidence for refraction from the water into the air. $$n_{water}sin \theta_i=n_{air}sin \theta_r$$ From the diagram given in the problem, we see that the refracted angle is $77^{\circ}$. Remember, we measure all angles off the normal to the surface. $$1.33sin \theta_i=1.00sin77^{\circ}$$ $$ \theta_i=47.11^{\circ}$$ From the diagram given in the problem, we find the depth D of the pool. $$tan 47.11^{\circ}=\frac{6.50m}{D}$$ $$D=6.04m$$
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