Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 21 - Electromagnetic Induction and Faraday's Law - Problems - Page 622: 61

Answer

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Work Step by Step

Use equation 21–15, without a capacitive reactance. The inductor’s reactance is given by equation 21–11b. a. $$Z=\sqrt{R^2+X_L^2}=\sqrt{R^2+4\pi^2 f^2 L^2}$$ $$Z=\sqrt{(36\times10^3 \Omega)^2+4\pi^2 (50Hz)^2 (55\times10^{-3}H)^2}=3.6\times10^4\Omega$$ At this low frequency, the inductor has negligible effect. b. $$Z=\sqrt{R^2+X_L^2}=\sqrt{R^2+4\pi^2 f^2 L^2}$$ $$Z=\sqrt{(36\times10^3 \Omega)^2+4\pi^2 (3.0\times10^4 Hz)^2 (55\times10^{-3}H)^2}=3.7\times10^4\Omega$$
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