Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 21 - Electromagnetic Induction and Faraday's Law - Problems - Page 622: 59

Answer

a. $7400\Omega$ b. $0.38A$

Work Step by Step

a. Find the reactance of a capacitor with equation 21–12b. $X_C=\frac{1}{2 \pi f C}=\frac{1}{2 \pi (720Hz) (0.030\times10^{-6}F)}=7400\Omega$ b. Find the peak value of the current using Ohm’s law. $$I_{peak}=\sqrt2I_{rms}=\sqrt2\frac{V_{rms}}{X_C}$$ $$=\sqrt2\frac{2.0\times10^3V}{7368\Omega}=0.38A$$
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