Answer
$l_T=46m$, $l_w=21km$, $R=7.0×10^2\Omega$
Work Step by Step
$L=\frac{\mu_oN^2A}{l_T}$
$A=\frac{\pi(d_T)^2}{4}$
$l_T=d_wN$
$L=\frac{\mu_oN^2(\frac{\pi(d_T)^2}{4})}{d_wN}$
$N=\frac{4d_wL}{\mu_o\pi d_T^2}=56993$ turns
$l_T=d_wN=(0.81\times10^{-3}m/turn)(56993 turns)=46m$
$l_w=\pi d_TN=pi(12\times10^{-2}m/turn)(56993 turns)=21km$
$R=\rho\frac{l}{A}=(1.68\times10^{-8}\Omega m)\frac{21486m}{(\frac{0.81\times10^{-3}m}{2})^2}=7.0\times10^2\Omega$