Answer
451V, 56.4 A.
Work Step by Step
Use equation 21-6 to relate the turns ratio to the voltage ratio.
$$\frac{N_S}{N_P}=\frac{V_S}{V_P}$$
$$V_S=V_P\frac{N_S}{N_P}=(120V)\frac{1240turns}{330turns}=451V$$
Use equation 21-7 to relate the turns ratio to the current ratio.
$$\frac{N_P}{N_S}=\frac{I_S}{I_P}$$
$$I_P=I_S\frac{N_S}{N_P}=(15.0A)\frac{1240turns}{330turns}=56.4A$$