Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 21 - Electromagnetic Induction and Faraday's Law - Problems - Page 621: 33

Answer

451V, 56.4 A.

Work Step by Step

Use equation 21-6 to relate the turns ratio to the voltage ratio. $$\frac{N_S}{N_P}=\frac{V_S}{V_P}$$ $$V_S=V_P\frac{N_S}{N_P}=(120V)\frac{1240turns}{330turns}=451V$$ Use equation 21-7 to relate the turns ratio to the current ratio. $$\frac{N_P}{N_S}=\frac{I_S}{I_P}$$ $$I_P=I_S\frac{N_S}{N_P}=(15.0A)\frac{1240turns}{330turns}=56.4A$$
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