Answer
$9.6\times10^{-3}T$
Work Step by Step
Use equation 20–8 for the magnetic field inside a solenoid.
$$B=\frac{\mu_oNI}{\mathcal{l}}=\frac{(4\pi \times10^{-7} T\cdot m/A)(460)(2.0A)}{0.12m}$$
$$=9.6\times10^{-3}T$$
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