Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 20 - Magnetism - Problems - Page 584: 25

Answer

$2.9\times10^{-4}T$

Work Step by Step

Model the jumper cable as a long straight wire. Use equation 20–6. $$B=\frac{\mu_oI}{2\pi r}$$ $$=\frac{(4\pi \times10^{-7} T\cdot m/A)(65A)}{2\pi (4.5\times10^{-2}m)}$$ $$=2.9\times10^{-4}T$$ Taking a ratio, we see that this is about 5.8 times the strength of the Earth's magnetic field.
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