Answer
a. $4.7\times10^{-5}m/s$
b. $1.1\times10^{29}\frac{e^-}{m^3}$
Work Step by Step
a. See page 569. Solve for the drift velocity, v, in the Hall effect equation.
$$V_{Hall}=vBd$$
$$v=\frac{V_{Hall}}{Bd}$$
$$=\frac{1.02\times10^{-6}V}{(1.2T)(0.018m)}=4.7\times10^{-5}m/s$$
b. Find the charge carrier density by using equation 18–10.
$$n=\frac{I}{eAv_d}$$
$$=\frac{15A}{(1.60\times10^{-19}C)(0.018m)(0.0010m)( 4.722\times10^{-5}m/s)}$$
$$=1.1\times10^{29}\frac{e^-}{m^3}$$