Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 20 - Magnetism - Problems - Page 583: 5

Answer

$27^{\circ}$

Work Step by Step

The maximum force occurs when the current is perpendicular to the magnetic field, and the sine of the angle is 90 degrees. See equation 20-2. Here, $\frac{F}{\mathcal{l}}=0.45\frac{F_{max}}{\mathcal{l}}$ Use equation 20-1 and solve for the force per meter. $$\frac{F}{\mathcal{l}}=IBsin\theta=0.45IB$$ $$\theta=sin^{-1}0.45 = 27^{\circ}$$
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