#### Answer

abc. Negative x, speeding up, negative acceleration.
def. Positive x, speeding up, positive acceleration.
g. No change, speed is zero, acceleration is zero.

#### Work Step by Step

abc. During the interval from A to B, it is moving in the negative x-direction (its displacement is negative), speeding up (the magnitude of the slope of the x-t graph is increasing), and the acceleration is negative (the position-time graph is concave down).
def. During the interval from D to E, it is moving in the positive x-direction (its displacement is positive), speeding up (the magnitude of the slope of the x-t graph is increasing), and the acceleration is positive (the position-time graph is concave up).
g. During the interval from C to D, the object is not moving at all, remains stationary, and the acceleration is zero.