Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 45: 43

Answer

t = 1.09 seconds

Work Step by Step

To find the time to fall from a height of 1.45 meters, we can use this equation: $y = \frac{1}{2}at^2$. We will rearrange the equation to make $t$ the subject of the equation and then solve: $t^2 = \frac{2y}{a} = \frac{2\times1.45}{9.80} = 0.296$ $t = \sqrt{0.296} = 0.544 ~s$ The time to jump up and fall back down to the ground is double the time it takes to fall. $t_{total} = 2\times0.544 = 1.09 ~s$ Therefore, the total time is 1.09 seconds.
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