Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 44: 40

Answer

(a) 8.81 seconds (b) 86.3 m/s

Work Step by Step

(a) $y = \frac{1}{2}at^2$ $t^2 = \frac{2y}{a} = \frac{2\times380}{9.80} = 77.55$ $t = \sqrt{77.55} = 8.81 ~s$ (b) $v = v_0 + at = 0 + 9.80\times8.81 = 86.3 ~m/s$
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