Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 44: 23

Answer

a) 1.2 $m/s^2$ b) 106 m

Work Step by Step

a) We solve using the equation: v = $v_{o}$ + at a = $\frac{v-v_{o}}{t}$ a = $\frac{21m/s - 14m/s}{6.0s}$ a = 1.2 $m/s^2$ b) We solve using the equation: x = $v_{o}t + \frac{1}{2}at^2$ x = $(14m/s)(6.0s) + \frac{1}{2}(1.2m/s^2)(6.0s)^2$ x = 106m
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.