Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems: 18

Answer

a. $6.52 \frac{m}{s^{2}}$ b. $8.45 \times 10^{4} \frac{km}{h^{2}}$

Work Step by Step

a. Find the average acceleration from equation 2–4. $$\frac{\Delta v}{\Delta t}=\frac{9.00 m/s- 0}{1.38 s}=6.52 \frac{m}{s^{2}}$$ b. $6.52 \frac{m}{s^{2}}\frac{1 km}{1000 m}(\frac{3600 s}{1 hr})^{2}=8.45 \times 10^{4} \frac{km}{h^{2}}$
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