Answer
a) Place Galvanometer in parallel with $7.0\times10^{-5}\Omega$ resistor to make ammeter to read currents up to 25A.
b) Place Galvanometer in series with $4.5\times10^6\Omega$ resistor to make voltmeter with full scale deflection of 250V.
Work Step by Step
a) $I=I_G+I_R=25A$
$V_R=V_G$
$I_R(R)=I_G(r)$
$(I-I_G)R=I_G(r)$
$(25A-55\mu A)R=(55\mu A)(32\Omega)$
$R=\frac{(55\mu A)(32\Omega)}{(25A-55\mu A)}=7.04\times10^{-5}\Omega$
Place Galvanometer in parallel with $7.0\times10^{-5}\Omega$ resistor to make ammeter to read currents up to 25A.
b) $R=\frac{V}{I}=\frac{250V}{55\mu A}=4.5\times10^6\Omega$
Place Galvanometer in series with $4.5\times10^6\Omega$ resistor to make voltmeter with full scale deflection of 250V.