Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - Problems - Page 555: 59

Answer

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Work Step by Step

a. The current in the galvanometer that produces full-scale deflection is the reciprocal of the reported sensitivity. $$I_{full-scale}=\frac{1}{35000\Omega/V}=2.9\times10^{-5}A$$ b. The resistance of the voltmeter is the full-scale voltage, 250V, multiplied by the reported sensitivity. $$R=V_{full-scale}(sensitivity)=(250V)( 35000\Omega/V)=8.8\times10^6\Omega$$
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