Answer
a) $V_1=6.63V$
$V_2=2.37V$
b) $Q_1=Q_2=3.32\mu C$
c) $V_1=V_2=9.0V$
$Q_1=4.5\mu C$
$Q_2=12.6\mu C$
Work Step by Step
a, b) $C_1=0.50\mu F$
$C_2=1.4\mu F$
$V_1+V_2=9.0V$
$Q_1=Q_2=Q_{eq}$
$C_{eq}=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}=0.368\mu F$
$Q_{eq}=C_{eq}V=(0.368\mu F)(9.0V)=3.32\mu C$
$Q_1=Q_2=Q_{eq}$
$V_1=\frac{Q_1}{C_1}=\frac{3.32\mu C}{0.50\mu F}=6.63V$
$V_2=V-V_1=2.37V$
c) $C_1=0.50\mu F$
$C_2=1.4\mu F$
$V_1=V_2=9.0V$
$Q=Q_1+Q_2$
$Q_1=C_1V=(0.50\mu F)(9.0V)=4.5\mu C$
$Q_2=C_2V=(1.40\mu F)(9.0V)=12.6\mu C$