Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - Problems - Page 553: 31

Answer

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Work Step by Step

Find the current through resistor 1 by applying Kirchhoff’s loop law. Start at the upper left corner and go around the outer loop counterclockwise. $$V_3-I_1R_1 +V_1=0$$ $$I_1=\frac{V_3+V_1}{R_1}=\frac{6.0V+9.0V}{22\Omega}=0.68A$$ The current goes from right to left. Find the current through resistor 2 by applying Kirchhoff’s loop law. Start at the lower left corner and go around the lower loop counterclockwise. $$V_3-I_2R_2 =0$$ $$I_2=\frac{V_3}{R_2}=\frac{6.0V}{18\Omega}=0.33A$$ The current goes from right to left.
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