Answer
See answers.
Work Step by Step
Find the current through resistor 1 by applying Kirchhoff’s loop law. Start at the upper left corner and go around the outer loop counterclockwise.
$$V_3-I_1R_1 +V_1=0$$
$$I_1=\frac{V_3+V_1}{R_1}=\frac{6.0V+9.0V}{22\Omega}=0.68A$$
The current goes from right to left.
Find the current through resistor 2 by applying Kirchhoff’s loop law. Start at the lower left corner and go around the lower loop counterclockwise.
$$V_3-I_2R_2 =0$$
$$I_2=\frac{V_3}{R_2}=\frac{6.0V}{18\Omega}=0.33A$$
The current goes from right to left.