Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - Problems - Page 552: 7

Answer

Two $10\Omega$ resistors in series.

Work Step by Step

First find the equivalent resistance of five $100\Omega$ resistors in parallel. When resistors are wired in parallel, we use equation 19–4 to find the equivalent resistance. $$\frac{1}{R_{eq}}=\frac{1}{100\Omega}+\frac{1}{100\Omega}+\frac{1}{100\Omega}+\frac{1}{100\Omega}+\frac{1}{100\Omega}$$ $$R_{eq}=20\Omega$$ Next consider the $10\Omega$ resistors in series. When resistors are wired in series, we use equation 19–3 to find the equivalent resistance. The resistances add. By dividing, $(20\Omega/10\Omega)$, we see that two $10\Omega$ resistors in series add up to give us the required $20\Omega$ resistance.
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