Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - Problems - Page 552: 4

Answer

8.8 volts

Work Step by Step

For resistors in series, the equivalent resistance is their sum: $R_{eq}=R_1+R_2$. The current in the entire circuit is the battery voltage divided by the equivalent resistance that it “sees”: $I=\frac{\epsilon}{R_{eq}}=\frac{\epsilon}{ R_1+R_2}$. Finally, the voltage across the one of the resistors, say, $R_2$, is given by Ohm’s law, V=IR. $$V_{R_2}=IR_2=\frac{\epsilon}{ R_1+R_2}R_2$$ $$ =\frac{12V}{650\Omega+1800\Omega}(1800\Omega)=8.8V$$
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