Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - Problems - Page 552: 2

Answer

The internal resistance of each cell is $0.33~\Omega$

Work Step by Step

Because the cells are in parallel, the total voltage in the circuit is $4\times ~1.5~V$ which is $6.0~V$. Let $R_0$ be the internal resistance of each cell. Then the total resistance in the circuit is $4R_0+12.0~\Omega$ We can use Ohm's law to find the internal resistance of each cell. $V = I~R$ $6.0~V = (0.45~A)(4~R_0+12.0~\Omega)$ $4~R_0 = \frac{6.0~V}{0.45~A} -12.0~\Omega$ $R_0 = \frac{6.0~V}{(4)(0.45~A)} -\frac{12.0~\Omega}{4}$ $R_0 = 0.33~\Omega$ The internal resistance of each cell is $0.33~\Omega$.
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