Answer
$Q_{2f}=8.47\mu C$
$Q_{1f}=15.5\mu C$
$V=7.06V$
Work Step by Step
$V_{1i}=V_{2i}=24V$
$Q=CV$
$Q_2i=C_2V_2$
$Q_{total}=Q_{1i}-Q_{2i}=Q_{1f}+Q_{2f}$
$C_1V_{1i}-C_2V_{2i}=Q_{1f}+Q_{2f}$
$(2.2\mu F)(24V)-(1.2\mu F)(24V)=Q_{1f}+Q_{2f}$
$Q_{1f}+Q_{2f}=24\mu C$
$\frac{Q_{1f}}{C_1}=\frac{Q_{2f}}{C_2}$
$Q_{1f}=\frac{Q_{2f}C_1}{C_2}$
$\frac{Q_{2f}C_1}{C_2}+Q_{2f}=24\mu C$
$Q_{2f}=8.47\mu C$
$Q_{1f}=15.5\mu C$
$V=\frac{Q_{1f}}{C_1}=\frac{15.5\mu C}{2.2\mu F}=7.06V$