Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - General Problems - Page 558: 92

Answer

$Q_{2f}=8.47\mu C$ $Q_{1f}=15.5\mu C$ $V=7.06V$

Work Step by Step

$V_{1i}=V_{2i}=24V$ $Q=CV$ $Q_2i=C_2V_2$ $Q_{total}=Q_{1i}-Q_{2i}=Q_{1f}+Q_{2f}$ $C_1V_{1i}-C_2V_{2i}=Q_{1f}+Q_{2f}$ $(2.2\mu F)(24V)-(1.2\mu F)(24V)=Q_{1f}+Q_{2f}$ $Q_{1f}+Q_{2f}=24\mu C$ $\frac{Q_{1f}}{C_1}=\frac{Q_{2f}}{C_2}$ $Q_{1f}=\frac{Q_{2f}C_1}{C_2}$ $\frac{Q_{2f}C_1}{C_2}+Q_{2f}=24\mu C$ $Q_{2f}=8.47\mu C$ $Q_{1f}=15.5\mu C$ $V=\frac{Q_{1f}}{C_1}=\frac{15.5\mu C}{2.2\mu F}=7.06V$
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