Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Problems - Page 523: 60

Answer

5 nW.

Work Step by Step

The power is the work done per unit time. The work done to move a charge Q against a potential difference V is QV. In this problem, we are given the charge density, so multiply by the effective surface area of the cell (length times circumference) to find the charge that is moved. $$P=\frac{W}{t}=\frac{QV}{t}=\frac{Q}{t}V$$ $$=3\times10^{-7}\frac{mol}{m^2\cdot s}(6.02\times10^{23}\frac{ions}{mol})(1.6\times10^{-19}\frac{C}{ion})(0.10m)\pi(20\times10^{-6}m)(0.030V)$$ $$=5\times10^{-9}W$$
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