Answer
330 volts
Work Step by Step
First find the rms current by using the relationship between peak and rms values, equation 18–8a.
$$I_{rms}=\frac{ I_{peak}}{\sqrt2}$$
$$ =\frac{6.4A}{\sqrt2 }$$
Next, relate the rms values to the power by using equation 19-9a.
$$P=I_{rms}V_{rms}$$
$$V_{rms}=\frac{P}{I_{rms}}$$
$$V_{rms}=\frac{1500W\sqrt2}{6.4A}=330V$$